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- Title
LET'S DO MATH - CRISPY CRISPS PROBLEM.
- Abstract
By multiplying 11/4 by 3/3, there is 33/12 left over-+ 33 x 1/12 which is morethan needed for 28 students (i.e., 28 x 1/12) - solution 2-4 using ratio table strategies- dividing by 2/2 and then multiplying by 3/3. solution 3-* focused on whole pans of Crisps remaining, using mixed fraction 2 3/4 to write as 12ths. - solution 1-4 using a paper-folding-like drawing to represent the pans of 8ths as pans of 4ths are divided down the middle and the remaining Crisps are split into 16ths and combined. 2//ili-a) 3/4 b) 3/3 c) 15/6 -trSolution 1 Solution 2 During (Working On It) 3/4 3/4 = (3/4) x (3/3) = liliWI 3/4 = 9/~2 (3x3)/(4x3) = 9/12 Crispy Crisps Problem 3/3 = (3/3) x (4/4) = On Day 1 of the Fun Fair, the Grade 593 -rrrT-r-r " 13 = 12/12 (3x4)/(3x4) = 12/12 5s took 7 pans of Crispy Crisps to 15/6 15/6 = (15/6) x (2/2) = sell.
- Subjects
MATHEMATICS
- Publication
Ontario Mathematics Gazette, 2021, Vol 59, Issue 4, p7
- ISSN
0030-3011
- Publication type
Article